Pure water is saturated with pure solid AgCl, a silver rod is placed in the solution and the potential is measured against normal calomel electrode at 25°C. This experiment is then repeated with a saturated solution of AgI. If the difference in potential in the two cases is 0.177 V, what is the ratio of solubilty product (K sp ) of AgCl and AgI at the temperature of the experiment ? (In both cases normal calomel electrode is cathod)
Text Solution
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Ag 
Ag + + e –
E 1 = E oxid + E calomel
= E' – 
log 
+ E calomel
E 2 = E' – 
log 
+ E calomel
E 2 – E 1 = 0.177 = 0.0591 log 
= 10 6 .
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